500+ OSS dependencies in an average app
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As before, increasing p in tandem with q (r = 1/2 to r = 4/8) buys us nothing, as the trick increments the nominator and the denominator by the same factor, still producing the same effective step; the solution is predicated on the lowest-denominator representation of r = p / q.，推荐阅读同城约会获取更多信息
Runtime evaluation support